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D( x )
(5^3*x-1)/2 <= 0
(5^3*x-1)/2 <= 0
(5^3*x-1)/2 <= 0
(125*x-1)/2 <= 0
( 125*x-1 )
125*x-1 <= 0 // + 1
125*x <= 1 // : 125
x <= 1/125
( 2 )
2 <= 0
x belongs to the empty set
(-oo:1/125) (1/125:+oo) 125*x-1 - + 2 + +
x in (1/125:+oo)
ln((5^3*x-1)/2) = 0
ln((5^3*x-1)/2) = ln(e^0)
(5^3*x-1)/2 = e^0
(5^3*x-1)/2-e^0 = 0
(125*x-1)/2-1 = 0
(125*x-1)/2+(-1*2)/2 = 0
125*x-1*2-1 = 0
125*x-3 = 0
(125*x-3)/2 = 0
(125*x-3)/2 = 0 // * 2
125*x-3 = 0
125*x-3 = 0 // + 3
125*x = 3 // : 125
x = 3/125
x = 3/125
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